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29-31x-5x^2=0
a = -5; b = -31; c = +29;
Δ = b2-4ac
Δ = -312-4·(-5)·29
Δ = 1541
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-\sqrt{1541}}{2*-5}=\frac{31-\sqrt{1541}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+\sqrt{1541}}{2*-5}=\frac{31+\sqrt{1541}}{-10} $
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